10t=-16t^2+40t

Solution for 10t=-16t^2+40t equation:

10t=-16t^2+40t

We move all terms to the left:

10t-(-16t^2+40t)=0

We get rid of parentheses

16t^2-40t+10t=0

We add all the numbers together, and all the variables

16t^2-30t=0

a = 16; b = -30; c = 0;
Δ = b2-4ac
Δ = -302-4·16·0
Δ = 900
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{900}=30$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-30)-30}{2*16}=\frac{0}{32}
=0
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-30)+30}{2*16}=\frac{60}{32}
=1+7/8
$